(3x+4)x+3x=11+3x^2-4

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Solution for (3x+4)x+3x=11+3x^2-4 equation: 


Simplifying
(3x + 4) * x + 3x = 11 + 3x2 + -4

Reorder the terms:
(4 + 3x) * x + 3x = 11 + 3x2 + -4

Reorder the terms for easier multiplication:
x(4 + 3x) + 3x = 11 + 3x2 + -4
(4 * x + 3x * x) + 3x = 11 + 3x2 + -4
(4x + 3x2) + 3x = 11 + 3x2 + -4

Reorder the terms:
4x + 3x + 3x2 = 11 + 3x2 + -4

Combine like terms: 4x + 3x = 7x
7x + 3x2 = 11 + 3x2 + -4

Reorder the terms:
7x + 3x2 = 11 + -4 + 3x2

Combine like terms: 11 + -4 = 7
7x + 3x2 = 7 + 3x2

Add '-3x2' to each side of the equation.
7x + 3x2 + -3x2 = 7 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
7x + 0 = 7 + 3x2 + -3x2
7x = 7 + 3x2 + -3x2

Combine like terms: 3x2 + -3x2 = 0
7x = 7 + 0
7x = 7

Solving
7x = 7

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '7'.
x = 1

Simplifying
x = 1

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